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95% CI for effect size (Est./S.E.)... |
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Mario posted on Sunday, September 11, 2016 - 3:07 am
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Dear users we are working with SEM. The output of the program give us the Estimate, S.E. and Est./S.E., which I interpret as to be the effect size. But, how to obtain the 95% Confidence Intervals (CI) of the effect size of each predictor? when I use the output 'CInterval' I get the lower and upper 0.5%, 2.5% and 5% CI for the estimators. Should I divide these, for example, Lower 2.5% CI by the SE of the estimate? For example, if Estimate=1.257; S.E.=0.373 and Effect size (Est./S.E.)= 3.365 (=1.257/0.373). And if Lower 2.5% CI of the estimate=0.525, can I say that Lower 2.5% CI of the effect size is 0.525/0.373?? thanks! |
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Effect size is typically defined as a mean difference divided by their SD, not Est/SE. So express that effect size in Model Constraint using model parameter labels and you will get a CI for it. If you are referring to standardized effects (stand'd slopes) you find them and their CI's in the regular output. |
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Mario posted on Monday, September 12, 2016 - 2:24 am
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Thanks Dr. Muthen, so, just to confirm my little knowledge. What you called standardized effects, is the Est./S.E provided by MPlus output, right? in Sweet and Grace-Martin (2011),I read that to report them "serves as standardized effect size statistics". In the SAMPSTAT output I get Estimate, S.E., Est./S.E. & the two-tailed P-value. I f I use CINTERVAL I get the same plus the CONFIDENCE INTERVALS of the estimates, but to get the CI of the standardized effects, should I divide these values by the SE of the estimate (the same I get with SAMPSTAT)? Thanks |
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Est/SE is not the standardized value. See the UG for a description of standardization. |
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Mario posted on Sunday, February 18, 2018 - 7:59 am
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Dear Dr. Muthen so, what is the meaning of EST./S.E. and how it should be interpreted? Thanks |
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See page 798 of the Version 8 User's Guide which you find on the Mplus website. |
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Mario posted on Monday, February 19, 2018 - 12:40 am
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Thanks! |
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