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| arif özer posted on Monday, January 19, 2015 - 3:39 pm
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I used WLSMV estimator when I performed CFA. I have two model. One of them is two-factor model (chi-square= 43.41, df=26) and the other is one-factor model (chi-square= 44.16, df=27). I applied chi-suare difference test by using m-plus guide. chi-square difference test = 62.18, df= 1; p=.00.
How it can be obtained!.. while there is only one point between two model.
Thanks |
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| Which version of Mplus are you using? |
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| arif özer posted on Monday, January 19, 2015 - 4:50 pm
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| Mplus 6.12 |
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| Please send the 2 outputs to Support along with your license number. |
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| arif özer posted on Tuesday, January 20, 2015 - 10:31 am
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| I bought the program as part of a project three years ago. As soon as I go the school, I'II send license number. |
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| arif özer posted on Tuesday, January 20, 2015 - 11:38 am
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| two output can't be send because of KB limit. Is there another posting way? |
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| You can zip it. Or, rerun with less output options requested. |
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| arif özer posted on Tuesday, January 20, 2015 - 1:36 pm
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1)
Mplus VERSION 6.12
MUTHEN & MUTHEN
01/20/2015 2:45 AM
INPUT INSTRUCTIONS
TITLE: CFA with
categorical factor indicators
DATA: FILE IS kf.dat;
VARIABLE: NAMES ARE M1-M9;
CATEGORICAL ARE M1-M9;
MODEL:
Ozfark BY M1 M2 M3 M4;
Kulfark BY M5 M6 M7 M8 M9;
SAVEDATA: DIFFTEST IS deriv.dat;
OUTPUT: STANDARDIZED;
Estimator WLSMV
THE MODEL ESTIMATION TERMINATED NORMALLY
MODEL FIT INFORMATION
Number of Free Parameters 39
Chi-Square Test of Model Fit Value 43.408*
Degrees of Freedom 26
P-Value 0.0175
RMSEA (Root Mean Square Error Of Approximation)
Estimate 0.058
90 Percent C.I. 0.024 0.087
Probability RMSEA <= .05 0.309
CFI/TLI
CFI 0.979
Chi-Square Test of Model Fit for the Baseline Model
Value 880.214
Degrees of Freedom 36
P-Value 0.0000
WRMR (Weighted Root Mean Square Residual)
Value 0.626
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| arif özer posted on Tuesday, January 20, 2015 - 1:41 pm
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2)
TITLE: CFA with categorical factor indicators
DATA: FILE IS kf.dat;
VARIABLE: NAMES ARE M1-M9;
CATEGORICAL ARE M1-M9;
ANALYSIS: DIFFTEST IS deriv.dat;
MODEL:
Ozfark BY M1 M2 M3 M4;
Kulfark BY M5 M6 M7 M8 M9;
Ozfark WITH Kulfark @ 0;
SUMMARY OF ANALYSIS
Number of groups 1
Number of observations 200
Number of dependent variables 9
Number of independent variables 0
Number of continuous latent variables 2
Estimator WLSMV
MODEL FIT INFORMATION
Number of Free Parameters 38
Chi-Square Test of Model Fit Value 250.591*
Degrees of Freedom 27
P-Value 0.0000
Chi-Square Test for Difference Testing Value: 62.184
df: 1
P: 0.0000
RMSEA Estimate 0.203
90 Percent C.I. 0.181 0.227
Probability RMSEA <= .05 0.000
CFI 0.735
WRMR 2.223 |
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Your postings are for two 2-factor models which only differ by a factor covariance being zero or not. Your initial question was about a 2-factor vs a 1-factor.
Also, we request posting in only 1 window. Longer issues should go to Support. |
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| arif özer posted on Tuesday, January 20, 2015 - 2:03 pm
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Ahem!...
execuse me ı try to use this forum. And thank you very much for your interest and reply.
My mainly interest is to compare 2-factor vs 1-factor. To solve it:
is it adequate that f1 WITH f2 @ 1; |
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| That's one approach sometimes usedm, if the WITH statement is referring to the correlation. But it is not a fully legitimate chi-2 difference test because corr=1 is on the border of the admissible parameter space. |
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