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arif özer posted on Monday, January 19, 2015 - 3:39 pm
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I used WLSMV estimator when I performed CFA. I have two model. One of them is two-factor model (chi-square= 43.41, df=26) and the other is one-factor model (chi-square= 44.16, df=27). I applied chi-suare difference test by using m-plus guide. chi-square difference test = 62.18, df= 1; p=.00. How it can be obtained!.. while there is only one point between two model. Thanks |
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Which version of Mplus are you using? |
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arif özer posted on Monday, January 19, 2015 - 4:50 pm
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Mplus 6.12 |
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Please send the 2 outputs to Support along with your license number. |
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arif özer posted on Tuesday, January 20, 2015 - 10:31 am
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I bought the program as part of a project three years ago. As soon as I go the school, I'II send license number. |
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arif özer posted on Tuesday, January 20, 2015 - 11:38 am
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two output can't be send because of KB limit. Is there another posting way? |
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You can zip it. Or, rerun with less output options requested. |
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arif özer posted on Tuesday, January 20, 2015 - 1:36 pm
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1) Mplus VERSION 6.12 MUTHEN & MUTHEN 01/20/2015 2:45 AM INPUT INSTRUCTIONS TITLE: CFA with categorical factor indicators DATA: FILE IS kf.dat; VARIABLE: NAMES ARE M1-M9; CATEGORICAL ARE M1-M9; MODEL: Ozfark BY M1 M2 M3 M4; Kulfark BY M5 M6 M7 M8 M9; SAVEDATA: DIFFTEST IS deriv.dat; OUTPUT: STANDARDIZED; Estimator WLSMV THE MODEL ESTIMATION TERMINATED NORMALLY MODEL FIT INFORMATION Number of Free Parameters 39 Chi-Square Test of Model Fit Value 43.408* Degrees of Freedom 26 P-Value 0.0175 RMSEA (Root Mean Square Error Of Approximation) Estimate 0.058 90 Percent C.I. 0.024 0.087 Probability RMSEA <= .05 0.309 CFI/TLI CFI 0.979 Chi-Square Test of Model Fit for the Baseline Model Value 880.214 Degrees of Freedom 36 P-Value 0.0000 WRMR (Weighted Root Mean Square Residual) Value 0.626 -------------------------------- |
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arif özer posted on Tuesday, January 20, 2015 - 1:41 pm
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2) TITLE: CFA with categorical factor indicators DATA: FILE IS kf.dat; VARIABLE: NAMES ARE M1-M9; CATEGORICAL ARE M1-M9; ANALYSIS: DIFFTEST IS deriv.dat; MODEL: Ozfark BY M1 M2 M3 M4; Kulfark BY M5 M6 M7 M8 M9; Ozfark WITH Kulfark @ 0; SUMMARY OF ANALYSIS Number of groups 1 Number of observations 200 Number of dependent variables 9 Number of independent variables 0 Number of continuous latent variables 2 Estimator WLSMV MODEL FIT INFORMATION Number of Free Parameters 38 Chi-Square Test of Model Fit Value 250.591* Degrees of Freedom 27 P-Value 0.0000 Chi-Square Test for Difference Testing Value: 62.184 df: 1 P: 0.0000 RMSEA Estimate 0.203 90 Percent C.I. 0.181 0.227 Probability RMSEA <= .05 0.000 CFI 0.735 WRMR 2.223 |
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Your postings are for two 2-factor models which only differ by a factor covariance being zero or not. Your initial question was about a 2-factor vs a 1-factor. Also, we request posting in only 1 window. Longer issues should go to Support. |
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arif özer posted on Tuesday, January 20, 2015 - 2:03 pm
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Ahem!... execuse me ı try to use this forum. And thank you very much for your interest and reply. My mainly interest is to compare 2-factor vs 1-factor. To solve it: is it adequate that f1 WITH f2 @ 1; |
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That's one approach sometimes usedm, if the WITH statement is referring to the correlation. But it is not a fully legitimate chi-2 difference test because corr=1 is on the border of the admissible parameter space. |
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