Message/Author 

Daisy Chang posted on Tuesday, November 08, 2005  4:21 pm



Hi, I am trying to do a second order factor model, but I constantly receiving an error message saying that THE STANDARD ERRORS OF THE MODEL PARAMETER ESTIMATES COULD NOT BE COMPUTED. THE MODEL MAY NOT BE IDENTIFIED. CHECK YOUR MODEL. PROBLEM INVOLVING PARAMETER 10. I have tried different ways including changing the starting value and fixing the loading of bpress to be 1, but none of it worked. I would really appreicate your input. Thanks. Here is my program. title: project data: file is u:\bio.dat; variable: names are HDL_CHO HB_A1C DHEA_S CORTIS1 NOREPI1 EPINEP1 BP_S BP_D WAISTHIP TOTHDL age control edu; usevariables are lncor lnnor lntot sqep sbp_s sbp_d lnhb sqdh sqep ; missing are all (9999); define: lncor= log(cortis1) if cortis1 > 0 then lncor = log(cortis1); lntot= log(tothdl) if tothdl > 0 then lntot= log(tothdl); lnnor= log(norepi1) if norepi1 > 0 then lnnor = log(norepi1); lnhb = log(hb_a1c) if hb_a1c > 0 then lnhb = log(hb_a1c); sqep = sqrt(epinep1) if epinep1 >=0 then sqep = sqrt(epinep1); sqdh = sqrt(dhea_s) if dhea_s >= 0 then sqdh = sqrt(dhea_s); sbp_s = (bp_s)/50 if bp_s > 0 then sbp_s = (bp_s)/50; sbp_d = (bp_d)/50 if bp_d > 0 then sbp_d = (bp_d)/50; analysis: type = missing h1; convergence=1000; model:bpress by sbp_s sbp_d; hpa by sqdh lncor; metabo by lnhb lntot waisthip; nerv by sqep lnnor; age by hpa* bpress metabo nerv; age@1; 


You would need to send your input, data, output, and license number to support@statmodel.com to get an answer to this question. 


Hi, we are establishing a 2nd order model. We've done CFA for seven tests separately and now try to model them in one SEM. The structure is as follows: f1 BY x1 x2 x3; f2 BY y1 y2 y3; ... f7 BY z1 z2 z3; g BY f1 f2 ...f7; The model fits our data well. However, loadings of all items from the last test on its latent factor are negative (all z are negative). Hence, f7 loads negatively on the second order factor g when all other loadings (f1 to f6)are positive. What could be the reason for this result? Does it have implications for further analyses? Thank you very much for your help. 


If all are negative, they can all be changed to positive. I would try positive starting values. 


Hi, I am new to Mplus (and SEM in general) and I was wondering if it is possible to integrate secondorder factors in a SEM: FOR EXAMPLE: variables v1 v2 v3 v4 v5 v6 v7 v8 v9 v10 v11 v12 v13 v14 v15 v16 v17 v18 v19 v20; f1 by v1 v2 v3; f2 by v4 v5 v6; f3 by v7 v8 v9; f4 by v10 v11; f5 by v12 v13 v14; f6 by v15 v16 17; f7 by v18 v19 v20; f8 by f1* f2 f3; f8 @1; f9 by f4* f5 f6; f9 @1; F9 on F8; F8 on F6 F7; Thank you very much for your help! Sarah 


Yes. See Example 5.6 in the user's guide. 


Hi again, I am sorry to bother you again. I just want to make sure my question was clear. As you suggested, I looked at chapiter 5 in the user's guide. It has a section on CFA (including second order factors: 5.6) and a section regarding SEM (structural paths). I do not see anything that combines both secondfactor AND structural models like the syntax I gave in example in the previous post. Sorry and thank you again. Sarah 


You can combine them. Run the analysis. If you have a problem, send it along with your license number to support@statmodel.com. 


Dear Mrs. Muthen, I'm new to Mplus an SEM, and hope that you can help reagarding the following question: I did a secondorder factor analysis with the following structure f1 by x1x3; f2 by x4x6; .. f4 ..x10x12; f5 by f1f4; ...and I have a qestion regarding the standardized model results: the estimate value for one of the first order factor (f2) on the second order factor (f5) is bigger than one. since I expected all loadings/estimates on the second order factor to be <1, I don't know how to interpret the result. what does this mean? Thank you very much! Patric 


See our FAQ on this: Stand'd greater than 1. 


Thanks a lot for your quick reply! That helped! 

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