Michelle posted on Friday, January 20, 2006 - 2:36 pm
I am trying to run a multi-group path model with all observed variables. When I constrain the parameters to be equal, the model runs fine. But when I try to free the parameters across groups, the model will not converge. Could you please tell me what is wrong with my code? (note, I have also tried it without the corr between inv and genn). thanks
USEVARIABLES ARE cluster weight inv use gen t1achvt t2achvt;
CATEGORICAL IS inv;
CLUSTER is cluster; WEIGHT is weight;
MISSING IS .;
GROUPING IS sex (0 = male 1 = female);
model: inv on use; inv on t1achvt; inv with gen; gen on t1achvt; t2achvt on inv; t2achvt on t1achvt; t2achvt on gen;
model male: inv on use; inv on t1achvt; inv with gen; gen on t1achvt; t2achvt on inv; t2achvt on t1achvt; t2achvt on gen;
I would suggest you run the model separately for each group and see if they each converge. If they do, and the multiple group run does not converge, there are some suggestions in the user's guide about convergence problems. If these do not work, send the outputs for each group, the output for the multiple group run, the data, the input for the multiple group run, and your license number to email@example.com
I have the same problem as Michelle. I have a 3 factor model. I am comparing two groups and when I try to freely estimate the loadings across the two groups, the model will not converge, even after 500000 iterations. I have tried assigning starting values to the loadings in the second group but this was unsuccessful. However, when I constrain the loadings in the second group, the model converges.
Oddly, If I reverse the order of the groups in the 2 group comparison, the model will converge.
Is there any information available from the work done on Michelle's problem?
I would suggest doing each group separately. With multiple group analysis, the first step is to determine whether a model with the same number of factors fits the data for each group. You can start with EFA or CFA. If each group has the same number of factors, then see if the same model fits the data for each group. Only then would I put the groups together to test for measurement invariance. Also, see the suggestions in the user's guide for convergence problems. If you continue to have problem, send your input, data, output, and license number to firstname.lastname@example.org.
Unfortunately, the ethics approval for my project prohibits sending data to external parties. This is why I was hoping that the recommendations that were made to solve Michelle's problem - which sounded exactly like my problem - might be available to give me a starting point to solve my problem.
I get a message about the model not converging, bu the best LL value was replicated. Can I proceed with invariance testing?
The messages are below:
736 perturbed starting value run(s) did not converge.
THE STANDARD ERRORS OF THE MODEL PARAMETER ESTIMATES MAY NOT BE TRUSTWORTHY FOR SOME PARAMETERS DUE TO A NON-POSITIVE DEFINITE FIRST-ORDER DERIVATIVE PRODUCT MATRIX. THIS MAY BE DUE TO THE STARTING VALUES BUT MAY ALSO BE AN INDICATION OF MODEL NONIDENTIFICATION. THE CONDITION NUMBER IS -0.233D-15. PROBLEM INVOLVING THE FOLLOWING PARAMETER: Parameter 18, %CG#1.C#3%: SERIOUS (equality/label)
And here is the model input pertaining to the above warning:
%OVERALL% c#1 on cg#1; c#2 on cg#1; G By common* serious; G@1; [G@0];
%cg#1.c#3% G by common* serious; [common serious] (m5-m6); common serious (v5-v6);
Hi! I am trying to run a multigroup analyses with no constrains to start with, as follows Grouping = PhysVlnce (0 = g1 1 = g2); ANALYSIS: Estimator = mlr; ...
MODEL: "...factor models for the latents: Socioeco and Support.." Socioeco on Age Sex; Support on Socioeco Cohabit Age Sex; Anx on Support Socioeco Age Sex; Dep on Socioeco Support Age Sex;
I recive the following error message:
THE MODEL ESTIMATION TERMINATED NORMALLY
THE STANDARD ERRORS OF THE MODEL PARAMETER ESTIMATES COULD NOT BE COMPUTED. THE MODEL MAY NOT BE IDENTIFIED. CHECK YOUR MODEL. PROBLEM INVOLVING THE FOLLOWING PARAMETER: Parameter 80, Group G2: [ HSCL_DEP ]
THE CONDITION NUMBER IS -0.518D-11. THE ROBUST CHI-SQUARE COULD NOT BE COMPUTED.