MLR acronym?
Message/Author
 Alyson Zalta posted on Friday, April 13, 2007 - 5:29 pm
Hello,
I'm reporting SEM results that were calculated with the MLR estimator. While this may seem trivial, I haven't been able to find what the MLR acronym stands for. I'd guess that it stands for "Maximum Likelihood Robust", but I want to ensure that I cite it properly. If you could please let me know, I'd appreciate it.
Thanks!
 Linda K. Muthen posted on Saturday, April 14, 2007 - 7:52 am
I don't think MLR is an acronym. It is an Mplus option for maximum likelihood estimation with robust standard errors.
 Francis Huang posted on Monday, March 23, 2009 - 4:05 pm
I am running a two level MLSEM. I have slightly nonnormal continuous data and from what I understand, using a Satorra-Bentler x2 with robust standard errors should be used. Mplus has this under the MLM estimator.

However, in a two level analysis, MLM is not available, but MLR is. In the manual, MLR also provides robust standard errors.

My question is: how is MLR related to MLM (in short-- how do I write this up aside from saying that I used a maximum likelihood estimator with robust standard errors)?
 Linda K. Muthen posted on Monday, March 23, 2009 - 4:22 pm
MLM – maximum likelihood parameter estimates with standard errors and a mean-adjusted chi-square test statistic that are robust to non-normality. The MLM chi-square test statistic is also referred to as the Satorra-Bentler chi-square.

MLR – maximum likelihood parameter estimates with standard errors and a chi-square test statistic (when applicable) that are robust to non-normality and non-independence of observations when used with TYPE=COMPLEX. The MLR standard errors are computed using a sandwich estimator. The MLR chi-square test statistic is asymptotically equivalent to the Yuan-Bentler T2* test statistic.

See the Yuan and Bentler paper referenced in the user's guide. MLR is an extension of MLM that can include missing data.
 Francis Huang posted on Tuesday, March 24, 2009 - 3:10 pm
Thanks for the info.

I have a follow up question. I am using MPLUS 5.2 and it displays the two-tailed p value-- how is it possible that in the unstandardized output-- it is nonsignificant (p>.05) and then in the standardized results, it is significant (p<.05)?

I am modeling achievement (ACHW and ACHB) defined by reading and math at two levels (student and school level) and I am using the presence of basic facilities at the school level as a predictor (i.e., presence of electricity, 1=yes, 0=no).

Unstd
ACHB ON
ELECTRIC 1.438 0.864 1.664 0.096

STDY Standardization
ACHB ON
ELECTRIC 1.185 0.585 2.028 0.043

StdYX
ACHB ON
ELECTRIC 0.488 0.241 2.027 0.043

Thank you.
 Bengt O. Muthen posted on Tuesday, March 24, 2009 - 7:19 pm
The unstandardized and standardized values have different sampling distributions and can give somewhat different z values.
 Francis Huang posted on Tuesday, March 24, 2009 - 8:01 pm
If that is the case, which one should be 'trusted' and interpreted?
 Bengt O. Muthen posted on Wednesday, March 25, 2009 - 8:36 am
I would go with the tests for the unstandardized coefficients, but I haven't seen this studied. It could be a good methods research project, simulating data to see for which type of coefficient the z tests behave best at different sample sizes.
 Paul A.Tiffin posted on Thursday, April 08, 2010 - 12:35 pm
I was just wondering, if you use mlr as the estimator method on a regression or path analysis is it still helpful to center explanatory variables?
 Bengt O. Muthen posted on Thursday, April 08, 2010 - 2:11 pm
I don't see that the MLR choice and centering choice are related.
 Paul A.Tiffin posted on Friday, April 09, 2010 - 12:22 am
 Wayne deRuiter posted on Thursday, July 22, 2010 - 7:31 pm
Hello,

If you use the estimator MLR without using the Type=Complex option, can you still get standard errors that are robust to non-normality and non-indepenence of observations?

Thanks
Wayne
 Linda K. Muthen posted on Friday, July 23, 2010 - 8:36 am
No, without TYPE=COMPLEX MLR is robust only to non-normality.
 Alexander Kapeller posted on Sunday, April 10, 2011 - 9:20 am
hello,

is the type=complex option required in the case of missing data (mcar or mar) or not.

Thanks
alex
 Linda K. Muthen posted on Sunday, April 10, 2011 - 10:10 am
All missing data estimation using maximum likelihood assumes MAR.
 Till posted on Tuesday, September 13, 2011 - 11:47 am
Dear Mrs. or Mr. Muthén,

I'm running a latent growth curve analysis. This is the Input:

Variable: names= g1 e1 n1 g2 e2 n2 g3 e3 n3 l01 l02 l03 l04 l05 l06 l07 l08 l09;
usevariable=all;
missing=all(99);

model: i s | l01@0 l02 l03 l04 l05@-1 l06 l07 l08 l09;
F1 by n1 n2 n3;
F2 by e1 e2 e3;
F3 by g1 g2 g3;
i s on F1 F2 F3;

Analysis:
Estimator=MLR;

output: samp standardized tech4;

I would like to use the MLR estimator because the mardia coefficient shows me that I can't assume multivariate normal distribution for my data. Is the use of the MLR Estimator appropriate here or do I have to use the normal ML?

Till
 Munajat Munajat posted on Monday, September 26, 2011 - 5:30 pm
Dear Dr. Bengt and Dr. Linda
In my model, I have 41 variables. 4 of them have kurtosis values > 3 (3.6, 3.6, 5.6 and 6.8). Do I need to run my model using MLM or MLV estimators? What is the rule of thumb to use the MLM/MLV instead of ML? What is the difference between MLM and MLV?
Thanks
 Linda K. Muthen posted on Monday, September 26, 2011 - 6:20 pm
There are three estimators that are robust to non-normality. Following are brief descriptions. Only MLR is available with missing data. This is what I would recommend.

• MLM – maximum likelihood parameter estimates with standard errors and a mean-adjusted chi-square test statistic that are robust to non-normality. The MLM chi-square test statistic is also referred to as the Satorra-Bentler chi-square.
• MLMV – maximum likelihood parameter estimates with standard errors and a mean- and variance-adjusted chi-square test statistic that are robust to non-normality
• MLR – maximum likelihood parameter estimates with standard errors and a chi-square test statistic (when applicable) that are robust to non-normality and non-independence of observations when used with TYPE=COMPLEX. The MLR standard errors are computed using a sandwich estimator. The MLR chi-square test statistic is asymptotically equivalent to the Yuan-Bentler T2* test statistic.
 SUSANA BARRADAS posted on Tuesday, April 07, 2015 - 6:12 pm
Hi Linda,
I just follow some of your previous suggestions about using WLSMV for a combination of continuous and categorical variables, in non normal distribution data. However, I´m not sure how to interpret the results as I didn´t get RMSEA, CFI,TLI or SRMR as I use to see using MLR estimate.

Susana
 Bengt O. Muthen posted on Tuesday, April 07, 2015 - 6:36 pm
WLSMV gives you chi-2, RMSEA, CFI, TLI. Perhaps you have an older version, or perhaps the run had a problem.
 SUSANA BARRADAS posted on Wednesday, April 08, 2015 - 7:41 am
Hi Linda, Thanks for your response. I´m trying another versión of the program, but I had this warning message: *** ERROR in VARIABLE command
The CATEGORICAL option is used for dependent variables only.
The following variable is an independent variable in the model.
Problem with: NSE
*** ERROR in VARIABLE command
The CATEGORICAL option is used for dependent variables only.
The following variable is an independent variable in the model.
Problem with: EDUCA

I´m using some demographics as education, sex and age to predict physical activity levels in my model. I don´t understand why categorical variables can only be dependent variables.

Many many thanks for your help!

Susana
 Linda K. Muthen posted on Wednesday, April 08, 2015 - 10:14 am
It is not that categorical variables can only be dependent variables. It is that the scale is only an issue for dependent variables. In regression, covariates can be binary or continuous. In all cases, they are treated as continuous and the model is estimated conditioned on them so that no distributional assumptions are made about them.
 SUSANA BARRADAS posted on Wednesday, April 08, 2015 - 12:36 pm
But I didn´t get any results with this data, only the warning message. That means that I should treat my categorical variables as continuous? In that sense, use MLR and do not introduce them as categorical?

Many thanks!

Susana
 Linda K. Muthen posted on Wednesday, April 08, 2015 - 6:21 pm
If you remove the CATEGORICAL option that has covariates on it, I think you will then get results. You cannot use WLSMV if you have no categorical dependent variables. Then you should use MLR.
 Daniel Lee posted on Thursday, September 29, 2016 - 10:54 am
Hi, I am conducting a latent growth model with 4 time points. At each time point, the the observed variables are skewed and departs from normality. In such a case, would you recommend I use MLR instead of ML?

Thank you!
 Linda K. Muthen posted on Thursday, September 29, 2016 - 11:04 am
Yes.
 Alexander Tokarev posted on Tuesday, February 07, 2017 - 8:17 am
Dear Linda and Bengt,

My sample is 508, and I am running a full mediation model: P->B->D. When estimating an indirect effect, bootstrapping cannot be used with MLR. Since it is known that MLR is robust to non-normality, I was wondering if MLR or MLM are also robust to the non-normality of the product term (PB * BD) in this case? In other words, can I be confident that a p value associated with an indirect effect is accurate when MLR or MLM are used? If so, is there any reference to back this up?

Alex
 Bengt O. Muthen posted on Wednesday, February 08, 2017 - 2:18 pm
To get bootstrapped SEs and CIs, you should use Estimator = ML. The acronym MLR is reserved for another type of SEs.
 Filipa Alexandra da Costa Rico Cala posted on Sunday, May 21, 2017 - 8:55 am
Dear Linda and Bengt,

For my PhD, I am performing multi-group analysis, as I want to test a model in two different countries. The dependent variable of my model is categorical. Firstly, I checked the invariance for each construct and now I am examining the invariance of regression coefficients and of one mediation. Because my data is not normal, and I have some missing values, for checking the invariance of my independent variables (which are continuous), I used the MLR estimator, and I used the WLMSV for the dependent variable. Could you please tell me if I can use the MLR with individual data (and not only with mixture models, which is the default estimator)?
Secondly, I also checked the full SEM model in each group, and I used the WLMSV and the bootstrap (because I have a mediation). Thus, could you please tell me if it is correct to use the MLR for examining the measurement invariance in each independent variable, and then in a later stage of my analysis, use the bootstrap procedure (for assessing if the mediation is significant)together with other estimator? I am asking this, because I know that the MLR estimator could not be run with bootstrap.
Once again, many thanks for your help,
 Bengt O. Muthen posted on Sunday, May 21, 2017 - 1:02 pm
You can use MLR. MLR can also be used with bootstrapping unless you have multilevel data or sampling weights.
 Filipa Alexandra da Costa Rico Cala posted on Monday, May 22, 2017 - 2:57 am
Thank you so much Bengt.
 Katie Gelman posted on Tuesday, May 23, 2017 - 12:08 pm
Hi Bengt,
I have a quick follow up question to your response from Filipa.

I am trying to run a mediated GMM, with a 3 class nominal outcome. I'm using dummy variables to account for school level clustering as I only have 7 total clusters.

When I try to add boostrap to my Analysis command, I get an error that "Bootstrap is not available for estimators MLM, MLMV, MLF and MLR", but your comment above makes it sound like it is? Any help would be wonderful.

Best,
Katie
 Linda K. Muthen posted on Tuesday, May 23, 2017 - 3:02 pm
Use ML. The other estimators have the same ML parameter estimates. ML with bootstrap gives you ML parameter estimates and bootstrapped standard errors.
 Jesus Garcia posted on Saturday, December 01, 2018 - 8:33 am
Hi Dr Muthen, I am trying to execute my model to determine the existing correlation between the 9 factors (80 variables Likert scale 0-5) and other factors measured in % referring to the use of transport modes, but the solution does not converge. I would like to know if the output is correct or that I should change so that my model is adjusted. This is the output:

USEVARIABLES ARE
act4 act5 act6 act9 act10 act11
act14 act15 act20 act26 act29 act30 act31 act34 act35 act36 act39 act40
act44 act45 act46 act49 act50
act54 act55 act56 act57 act59 act60
act64 act65 act66 act67 act68 act69 act70 act72 act73 act74 act75 act76 act77 act78 act79 act80 act152 act153 act154 act155 act156;

MISSING = ALL (99);
ANALYSIS:
TYPE = COMPLEX;
ESTIMATOR = MLR;

MODEL:
F1 BY act6 act11 act26 act31 act36 act46 act56 act66 act76;
F4 BY act4 act9 act14 act29;
F5 BY act5 act10 act15 act20 act30;
F9 BY act34 act39 act44 act49 act54;
F10 BY act35 act40 act45 act50 act55;
F12 BY act57 act67 act72 act77;
F13 BY act68 act73 act78;
F14 BY act59 act64 act69 act74 act79;
F15 BY act60 act65 act70 act75 act80;
COCHE BY act152;
COCHE_C BY act153;
TTP BY act154;
BICI BY act155;
PIE BY act156;
COCHE ON F1;

OUTPUT: STDYX; TECH4; MODINDICES(ALL);

Thank you!
 Bengt O. Muthen posted on Saturday, December 01, 2018 - 11:30 am
You have single-indicator factors:

TTP BY act154;
BICI BY act155;
PIE BY act156;

This gives you a factor variance and a residual variance for the indicator, creating a non-identification because you have only 1 observed variance. Either fix to zero the residual variance or don't create these factors but work directly with the observed variables.

 rgm smeets posted on Sunday, December 16, 2018 - 1:39 pm
Dear,

Could I use the mlf estimator on a dataset of more than 10,000 observations with skewed variables?
 rgm smeets posted on Monday, December 17, 2018 - 3:08 am
In addition to my last question, can the mlf estimator also deal with missing data?
 Bengt O. Muthen posted on Monday, December 17, 2018 - 4:49 pm
Yes - the whole ML family deals with missing data in the standard way assuming MAR ("FIML").
 rgm smeets posted on Tuesday, December 18, 2018 - 12:09 am
Dear mister Muthen,

I changed the estimator from MLR to MLF as I received the following warning:

WARNING: THE MODEL ESTIMATION HAS REACHED A SADDLE POINT OR A
POINT WHERE THE OBSERVED AND THE EXPECTED INFORMATION
MATRICES DO NOT MATCH. AN ADJUSTMENT TO THE ESTIMATION OF THE
INFORMATION MATRIX HAS BEEN MADE. THE CONDITION NUMBER IS - xxx- THE PROBLEM MAY ALSO BE RESOLVED BY DECREASING THE
VALUE OF THE MCONVERGENCE OR LOGCRITERION OPTIONS OR BY
CHANGING THE STARTING VALUES OR BY USING THE MLF ESTIMATOR.
THE MODEL ESTIMATION TERMINATED NORMALLY.

I have a dataset with more than ten thousand observations and some variables are skewed. If I use the MLF estimator, the statistical indicators and the model results are exactly the same as running the analysis with the MLR estimator (except for the SE).
What would you advise me to do? Use the MLF estimator? Or stick to the MLR estimator and ignore the warning?
 Bengt O. Muthen posted on Tuesday, December 18, 2018 - 5:26 pm
I would stick with the MLR estimator. The message may appear when convergence is not totally complete. You can sharpen Mconvergence to see if the logL improves and the message goes away. If not, ignore the message and stay with MLR.
 rgm smeets posted on Wednesday, December 19, 2018 - 10:08 am
Dear mister Muthen,

Thank you for this useful advice. How should I sharpen this Mconvergence? I read somewhere that I have to use: mconv = 0.0000001?
 rgm smeets posted on Wednesday, December 19, 2018 - 11:27 am
I decreased the value of mconv with factor 10 two times. A mconv of 0.00000001 makes the warning of the saddle point disappear but the LogL and the BIC is worse. I assume that I now best stick with the MLR and ignore the warning of the saddle point?
 Bengt O. Muthen posted on Wednesday, December 19, 2018 - 3:32 pm