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An issue I've run into for two separate sets of LCA models is a very large (e.g., over 1000) odds ratio resulting from the multinomial logistic model comparing a covariate effect on class membership. Specifically, the effect has been observed in two separate datasets when comparing effects of peer substance use on drug use class memberships when nonusers were treated as the reference condition. Conceptually, this makes sense (since nonusers typically do not have drug using friends in either data set). However, I'm wondering if I need to factor this issue into my model (e.g., constraining the relationship of peer use for nonusers, etc.)? Are there any examples where such constraints are used in the manual? 


This typically happens when a covariate has zero variance within one of the latent classes. Typically for a binary covariate. In line with regular logistic regression with an observed categorical dependent variable, this means that the slope for this covariate goes toward infinity. Mplus typically fixes such slopes at high values automatically. This does not complicate the interpretation because all this means is that the probability is 1 to be in a certain class when the covariate has one of its values and zero otherwise. 


Hello, I have had the same problem in relation to the odds ratio of an interaction term (in the millions!) that I have added to an LCA model (in the multinomial logistic regression part; I am using R3STEP). The interaction is of 2 binary observed variables. I am unclear as to how I should report this in my results. Any help appreciated. Many thanks, Dharmi 


An odds ratio in the millions is due to an odds in the numerator that is huge or an odds in the denominator that is tiny. In either case the odds ratio makes no sense. Just report that the two odds. 

Hyunok Ryu posted on Monday, December 07, 2015  11:38 pm



Hello, I wonder what exactly "*********" means in logistic regression odds ratio. Considering the other two classes have big odds ratio values (328.387 and 290.105), I assume it is big number but how big would it be approximately? Thank you. 


You can compute it from the estimated results. 

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