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Generating a new latent variable that... |
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Shige Song posted on Wednesday, December 20, 2006 - 9:19 pm
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the difference of another two latent variables. For example, I have two sequential growth processes and I want to get the difference of the two intercepts: ---------------- level trend | ht0*-12 ht1*-11 ht2*-10 ht3*-9 ht4*-8 ht5*-7 ht6*-6 ht7*-5 ht8*-4 ht9*-3 ht10*-2 ht11@-1 ht12@0; i s | ht91@0 ht94@1 ht98*2; dif | i - level; ---------------- where "level" and "trend" are latent growth factors for the first process and "i" and "s" are latent growth factors for the second process. I want to create a new latent variable that is the difference of the two latent growth factors "level" and "i". Mplus reports that this is a syntax error "Unable to expand variable list: I - LEVEL" The interaction of two latent variables can be generated using the "xwith" statement, but I could not find how to get the difference between two latent variable . Thanks for any suggestions! Shige |
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You have to define a new factor that is equal to i - level. You can do that as follows: fdif by; fdif on i@1 level@-1; fdif@0; [fdif@0]; This defines the new factor fdif as fdif = 0 + 1*i-1*level+0 |
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Dear Mplus team, I have two personality traits (2 latent variable A B) and I want to generate 2 new latent variable that indicate the difference between these two variables(A-B and B-A). The difference should indicate how much one personality trait is higher than the other on each participant. Do you have any suggestion on the script? |
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Try Diff BY A@1 B@-1; |
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