Message/Author |
|
Sung Kim posted on Friday, September 14, 2012 - 5:23 pm
|
|
|
In the Mplus Users Guide (p. 540), "a minimum number of target values must be given for purposes of model identification." For example, "For the orthogonal TARGET rotation, the minimum is m(m-1)/2." I am a little confused. Is it "the minimum or less" or "the minumum or more"? For example, I have 6 orthogonal factors and the minimum is 15. Can I specify more than 15 target values? I guess it is 15 or less. Is that correct? |
|
|
You can specify more than the minimum but not less. So 15 or more. |
|
david posted on Thursday, February 14, 2013 - 6:36 am
|
|
|
Hello Dr's I am running an EFA over bootstrap samples. For each output loadings matrix i would like to be able to keep the same factors with each group of similarly loading variables i.e. to stop the factor / factor names 'jumping about'. Within R i do this by rotating to the original data loading matrix. I have tried this in mplus using the target rotation option but i dont think this is what its for - a model is not identified if i supply a target loading for each variable for each factor - or if it is possible whether i am doing it corretly. a bit of my (nonsense) code ANALYSIS: TYPE = general; ROTATION = target(orthogonal); MODEL: f1 BY var1 var2 var3 var4.... var1~0.857 var2~-0.099 var3~0.615 ... (*1); f2 BY var1 var2 var3 var4... var1~0.062 var2~0.204 var3~0.211 ... (*2); f3 by var1 var2 var3 var4... var1~0.125 var2~-0.068 var3~0 ... (*3); Am i pursuing a wrong path here? thnaks, david |
|
|
Mplus doesn't currently implement the bootstrap for EFA. If you have generated however your bootstrap samples you can get the bootstrap standard errors by analyzing them with external montecarlo using an ESEM model. You don't need to worry about factor names jumping around because that is taken care of within the program. For that take a look at Appendix D in http://www.statmodel.com/download/SEM-Asparouhov2009.pdf |
|
david posted on Friday, February 15, 2013 - 3:18 am
|
|
|
Thank you Tihomir. This is what i am looking for. Unfortunately i am having problems in getting the montecarlo method to run. The DOS screen indicates that the first sample is geting analysed but i then receive a warning 'The input setup produced syntax warnings/errors causing Mplus to abort.' I get the limited output when i run the commands below. 'INPUT READING TERMINATED NORMALLY Errors for replication with data file c:\myaddress warnings about zero cells *** FATAL ERROR FACTOR LOADING STARTING VALUES OF A FACTOR ARE ALL ZERO. LEASTSQUARES ALIGNMENT METHOD REQUIRES AT LEAST ONE NON-ZERO STARTING VALUE.' The model produces results if i run the commands (with montecarlo excluded) on the individual datasets. I have set up a directory with all bootstrap samples and a .dat file with a list of the bootstrap sample names - as is shown in ex12.6, part 2. Do the warnings over zero cells prohibit using montecarlo or do you notice an omission in my syntax? Sorry to bother you again and thanks for any help. bw, david Syntax: DATA: FILE = "c:\myaddress\listoffiles.dat"; TYPE = MONTECARLO; VARIABLE: NAMES = var1 var2 ....... var40; CATEGORICAL = var1 - var40; MISSING = .; MODEL: f1-f4 BY var1 - var40 (*1); ANALYSIS: ROTATION = oblimin; |
|
|
Please send the relevant files and your license number to support@statmodel.com. |
|
C. Lechner posted on Tuesday, June 07, 2016 - 2:30 am
|
|
|
I applied an ESEM with oblique target rotation and an ESEM model with geomin rotation to the same set of variables. I specified target loadings of 1, -1, or 0 for each variable and factor. In comparing the models, I noticed that the factor correlations between the EFA factors were very different. Despite strikingly similar patterns of primary and secondary loadings, correlations were roughly twice as high in the target rotated ESEM compared to the geomin rotated ESEM. Even in a CFA applied to the same set of variables, factor correlations were much lower than in the target-rotated EFA. Note that... a) my EFA model consists of a brief instrument measuring 5 factors by only 11 items (4 factors by 2 items, 1 factor by three items) b) the output gave no error message in any of the models, and model fit was good c) Increasing rstarts, riterations and iterations does not remedy this finding. Do you have any idea what the reason for this marked difference in factor intercorrelations is? Could it point to problems in identifying the optimal rotation? Thank you! |
|
|
Using -1 and 1 as targets is fairly unusual and you might be forcing in a strange rotation. Pick a minimum of 4 zero targets for each of the 5 factors and estimate teh target rotation again. I would guess that geomin is better as it picks more clear and independent dimensions. Note that fit is identical. If the loadings are the same the factor correlations will be the same. |
|
Juan Ramón posted on Monday, July 31, 2017 - 7:15 am
|
|
|
When I run this: MODEL: F1 BY i1 i5 i13 i16 i20 i23 i25 i30 i32 i3 i8 i10 i28 i4~0 i7~0 i11~0 i14~0 i17~0 i19~0 i22~0 i26~0 i29~0 i31~0 i2~0 i6~0 i9~0 i12~0 i15~0 i18~0 i21~0 i24~0 i27~0 i33~0 (*1); F2 BY i4 i7 i11 i14 i17 i19 i22 i26 i29 i31 i1~0 i5~0 i13~0 i16~0 i20~0 i23~0 i25~0 i30~0 i32~0 i3~0 i8~0 i10~0 i28~0 i2~0 i6~0 i9~0 i12~0 i15~0 i18~0 i21~0 i24~0 i27~0 i33~0 (*1); F3 BY i2 i6 i9 i12 i15 i18 i21 i24 i27 i33 i1~0 i5~0 i13~0 i16~0 i20~0 i23~0 i25~0 i30~0 i32~0 i3~0 i8~0 i10~0 i28~0 i4~0 i7~0 i11~0 i14~0 i17~0 i19~0 i22~0 i26~0 i29~0 i31~0 (*1); i3 WITH i8 i10 i28; i8 WITH i10 i28; i10 WITH i28; i2 WITH i6; i4 WITH i19; i26 WITH i29; I get this warning message: *** WARNING in MODEL command Fewer than 6 loadings have been given target values in EFA set *1. The model may not be identified. After that, I get all the results without problems. I don't understand why it says that "fewer than 6 loadings have been given target values". As I understand the code, much more than six have received 0 values (~0). Thank you very much. |
|
|
Please send the output and your license number to support@statmodel.com. |
|
|
Hi, I'm attempting to run an EFA with targeted rotation. The targets are based on a previously published factor analysis that uses the exact same variables in another sample. There are 37 scales, and I'm extracting a 10 factor solution. The analysis runs well in SPSS, but I want to use MPLUS so I can save the resulting factor scores. When I run the syntax, I get an error: no convergence/residual covariance matrix is not positive definite/chi-square is negative. The error indicates a problem with one of my variables. Inspecting the results shows it has a loading >1 on the first factor and 0 on all the others. It also has a negative residual variance (-3). All variables in the analysis are on a similar scale. Any thoughts on how I could address whatever is happening here? Thanks very much. |
|
|
Please send your output to Mplus Support along with your license number. Data too if possible. |
|
Bo Zhang posted on Thursday, June 20, 2019 - 8:35 am
|
|
|
Hi Dr. Muthen, I was trying to run a Monte Carlo simulation for categorical bifactor ESEM with target rotation. However, I encountered the following error: FACTOR LOADING STARTING VALUES OF A FACTOR ARE ALL ZERO. LEASTSQUARES ALIGNMENT METHOD REQUIRES AT LEAST ONE NON-ZERO STARTING VALUE. Do you have any idea what's going on and how can I solve this? Thank you very much. |
|
|
We need to see your full output - send to Support along with your license number. |
|
|
Hello, when I run this: ANALYSIS: type=GENERAL; estimator=WLSMV; rotation=TARGET; MODEL: f1 BY COM2 COM3 SC1 SC2 SC4 SC5 SC6 EM2~0 EM3~0 EM4~0 T1~0 T3~0 T4~0 T5~0 CALM1~0 CALM3~0 CALM4~0 CALM5~0 CALM6~0 SELF1~0 SELF2~0 SELF3~0 SELF5~0 SELF6~0 LIS1~0 LIS2~0 LIS3~0 LIS4~0 RA1~0 RA2~0 RA3~0 RA4~0 RA5~0(*1); f2 BY COM2~0 COM3~0 SC1~0 SC2~0 SC4~0 SC5~0 SC6~0 EM2 EM3 EM4 T1~0 T3~0 T4~0 T5~0 CALM1~0 CALM3~0 CALM4~0 CALM5~0 CALM6~0 SELF1~0 SELF2~0 SELF3~0 SELF5~0 SELF6~0 LIS1~0 LIS2~0 LIS3~0 LIS4~0 RA1~0 RA2~0 RA3~0 RA4~0 RA5~0(*1); f3 BY COM2~0 COM3~0 SC1~0 SC2~0 SC4~0 SC5~0 SC6~0 EM2~0 EM3~0 EM4~0 T1~0 T3~0 T4~0 T5~0 CALM1 CALM3 CALM4 CALM5 CALM6 SELF1~0 SELF2~0 SELF3~0 SELF5~0 SELF6~0 LIS1~0 LIS2~0 LIS3~0 LIS4~0 RA1~0 RA2~0 RA3~0 RA4~0 RA5~0(*1); f4 BY COM2~0 COM3~0 SC1~0 SC2~0 SC4~0 SC5~0 SC6~0 EM2~0 EM3~0 EM4~0 T1~0 T3~0 T4~0 T5~0 CALM1~0 CALM3~0 CALM4~0 CALM5~0 CALM6~0 SELF1 SELF2 SELF3 SELF5 SELF6 LIS1~0 LIS2~0 LIS3~0 LIS4~0 RA1~0 RA2~0 RA3~0 RA4~0 RA5~0(*1); f5 BY COM2~0 COM3~0 SC1~0 SC2~0 SC4~0 SC5~0 SC6~0 EM2~0 EM3~0 EM4~0 T1~0 T3~0 T4~0 T5~0 CALM1~0 CALM3~0 CALM4~0 CALM5~0 CALM6~0 SELF1~0 SELF2~0 SELF3~0 SELF5~0 SELF6~0 LIS1~0 LIS2~0 LIS3~0 LIS4~0 RA1 RA2 RA3 RA4 RA5(*1); |
|
|
f6 BY COM2~0 COM3~0 SC1~0 SC2~0 SC4~0 SC5~0 SC6~0 EM2~0 EM3~0 EM4~0 T1 T3 T4 T5 CALM1~0 CALM3~0 CALM4~0 CALM5~0 CALM6~0 SELF1~0 SELF2~0 SELF3~0 SELF5~0 SELF6~0 LIS1 LIS2 LIS3 LIS4 RA1~0 RA2~0 RA3~0 RA4~0 RA5~0(*1); , one variable was over 1 like this. MODEL RESULTS Two-Tailed Estimate S.E. Est./S.E. P-Value F1 BY SC2 1.002 0.063 15.817 0.000 I think that it is Heywood case. So I wanted to check the residual but couldn't find residual. how can I solve this? Thank you very much. |
|
|
We ask that postings be limited to one window. For longer output questions like this send your output to Support along with your license number. |
|
|
Thanks for your reply. you told me that the output send to Support. but I don't know where Support category in website and who is the person in charge. if you let me know, I'll send it. Thank you. |
|
|
Send your email to support@statmodel.com |
|
Back to top |