|
 |
Negative residual variance with ESEM |
 
|
Message/Author |
|
Tom Hess posted on Tuesday, June 20, 2017 - 10:42 am
|
|
|
I am attempting to perform MULTIPLE-GROUP ESEM WITH CONTINUOUS FACTOR INDICATORS FOLLOWING THE DIRECTIONS ON PAGE 99 OF THE MANUAL (SECTION 5.27). USING THAT SAME CODE, ALL WORKS WELL EXCEPT FOR A SMALL NEGATIVE RESIDUAL VARIANCE ON ONE INDICATOR FOR ONE OF THE THREE GROUPS. CAN I FIX THIS TO 0 JUST FOR THAT ONE GROUP IN ORDER TO COMPLETE THE MULTI-GROUP ANALYSIS? IF SO, HOW. HERE IS MY CODE, WITH C3 THE PROBLEMATIC VARIABLE IN THE 3RD GROUP: MODEL: F1 - F5 BY C1 E1 A1 O1 N1 A2 C2 E2 O2 N2 C3 E3 A3 N3 (*1); [f1 - f5@0]; model G1: O2 WITH O1; Model G2: F1 - F5 BY C1 E1 A1 O1 N1 A2 C2 E2 O2 N2 C3 E3 A3 N3 (*1); [C1 - N3]; Model G3: F1 - F5 BY C1 E1 A1 O1 N1 A2 C2 E2 O2 N2 C3 E3 A3 N3 (*1); [C1 - n3]; |
|
|
Try saying e.g. a1@0; within the group-specific Model statements. |
|
Tom Hess posted on Wednesday, June 21, 2017 - 6:11 am
|
|
|
I tried that and adding that single statement to the program results in it not running--the only output is a copy of the program. Without it, the program runs fine. This where I included the code: Model G3: F1 - F5 BY C1 E1 A1 O1 N1 A2 C2 E2 O2 N2 C3 E3 A3 N3 (*1); A3@0; [C1 - n3]; |
|
|
Instead of this, try using MODEL CONSTRAINT to keep the parameter greater than zero. See Example 5.28. |
|
Back to top |
|
|