Identification references PreviousNext
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 Bengt O. Muthen posted on Friday, February 23, 2001 - 10:16 am
A question came up about references discussing identification in SEM and I thought I'd post my answer here.

No really comprehensive and thorough references come to mind, perhaps because the topic is difficult to say something general about. In practice people are satisfied of empirical identification by the information matrix being non-singular. But the following classic references have bits and pieces of the puzzle:

- Wiley, D (1973). The identification problem for structural equation models... In Goldberger & Duncan (eds) Structural Equation Modeling in the Social Sciences (Seminar Press, NY) 69-73. ---This talks about the column rank of the derivative matrix for covariance elements by parameters.

- Joreskog, KG (1977). Structural equation models in the social sciences. In Krishnaiah (ed) Applications of Statistics. Amsterdam: Holland Publishing, 265-287. --Some general statements mostly

- Joreskog, KG (1979). Author's Addendum (to Confirmatory Factor Analysis, the 1969 Psychometrika article). In Magidson (ed), Advances in Factor Analysis and Structural Equation Models. Cambridge, Mass: Abt Books. ---This has a little more detail than is typical.

More recently,

- Bartholomew's book Latent Variable Models and Factor Analysis (Griffin, 2nd ed.) has some more general identifiability sections.

I invite others to add more good references.
 Anonymous posted on Tuesday, April 16, 2002 - 9:29 am
What methods does Mplus use to solve overidentified models / SEMs ?

I've been running a rather large SEM with latent variables and have noticed that one or two portions of the model are overidentifed. Mplus doesn't return any error messages, the model converges without difficulty, and all the parameter estimates appear to be well-behaved. I'm wondering if the estimates for the coefficients are valid.

 Linda K. Muthen posted on Tuesday, April 16, 2002 - 12:37 pm
I assume you mean underidentified, that is, not identified. A part of the model can be not identified if analyzed alone but can become identified when it is part of a larger model. For example, a factor model with two indicators is not identified but a model with two factors each with two indicators is identified due borrowing information from each other. If this does not answer your question, let me know. If Mplus does not complain about the model not being identified, it is most likely identified.
 Anonymous posted on Tuesday, April 16, 2002 - 2:04 pm
I am using Hanushek and Jackson's definition of "overidentified".

In a "just identified" model, you have an equal number of equations and unknowns, thus you can get a unique solution for each unknown for all the information provided in the model.

In an "overidentified" model, you have more equations than unkowns, which at first blush appears to be a good thing -- you have many different ways of obtaining estimates for your unknown quantities. A problem occurs with overidentified models because with sample data, the errors and variances are not the same across variables. Recommended ways of obtaining solutions include two-stage least squares (TSLS), indirect least squares (ILS), etc.

Thus, I'm wondering how Mplus obtains parameter estimates in the overidentified case.
 Linda K. Muthen posted on Tuesday, April 16, 2002 - 2:21 pm
A model with more unknowns (parameters) than equations (sample statistics) is not identified and will not be estimated by Mplus. A model with less unknowns than equations will be estimated if it is identified using maximum likelihood or weighted least squares.
 Jason posted on Thursday, November 06, 2003 - 4:15 am
Very simple question from a new user. If I have a single indicator of a construct to be used in a larger SEM mediation model that has other latent constructs with multiple indicators, what is the best way to identify it. I tried fixing the factor loading of the single indicator to "1", but the model said it could not estimate the error variances. Suggestions?
 Linda K. Muthen posted on Saturday, November 08, 2003 - 5:24 pm
You do not need to create a latent variable if you have a single indicator. Just use the observed variable in the analysis and Mplus will take care of it. The only reason you would want to create a latent variable behind a single indicator is if you wanted to fix the residual variance to a value that reflects the reliability of the measure.
 Patrick Sturgis posted on Friday, January 23, 2004 - 8:27 am

following on from this last posting, I was wondering if you could tell me how one goes about fixing the residual variance to reflect a previous estimate of reliability. I have tried the following (fixing error variance at 0.3) and it does not seem to work (model does not converge):

latent by x1@1;
error by x1@1;
 Linda K. Muthen posted on Friday, January 23, 2004 - 9:16 am
f BY y@1;

where a is the error variance in y chosen as
a = (1 – reliability) * sample variance
 Anonymous posted on Thursday, March 04, 2004 - 2:57 pm
I’d like to pick up the discussion singular information matrices and identifiability again.

You said above that the model is probably identified if Mplus does not report any error messages, but I am wondering what types of error messages to look for/will come up when a model is not identified.

1. Is it correct to conclude that even if a model estimation terminates normally and yeilds fit statistics, class counts and memberships, model results (e.g., thresholds and/or proportions, the regression model part, etc.) … WHENEVER you get an error message in Tech11 that states that the information matrix with one less class is singular, this is always empirical evidence that the model is unidentified?

2. If this statement is true, when I encountered this error message I noted that Mplus still reported Estimates, S.E., and Est./S.E. when the model was not identified, but did not report Std or StdYX. Is the absence of values for Std and StdYX in the output another was to tell that a model is not identified?

3. Is Tech11 the only place in the output that indicates whether the information matrix with one less class is singular (or that indicates in some way that the model is not identified)? If so, is it true that the only was to determine that the information matrix is non-singular by making sure that there are no error messages in Tech11?

Thanks in advance. This discussion has been very helpful.
 bmuthen posted on Thursday, March 04, 2004 - 6:21 pm
1. The usual non-identifiability message in the regular results section refers to the k-class model - use that. Tech11 refers to the k-1 class model.

2. My answer to 1. also answers 2 - SE's are not reported when the model (the k-class model) is not identified.

3. A better way to check if the k-1 class model is identified is to run it (without Tech11).
 Anonymous posted on Thursday, September 30, 2004 - 11:49 am
Hi Linda,

i have the following model and I am using m-plus version 3.



 Linda K. Muthen posted on Thursday, September 30, 2004 - 3:34 pm
You should add one term and at time because the modification indices for the other terms may change when a term is added. Mplus will notify you if the model is not identified.
 Anonymous posted on Monday, November 15, 2004 - 9:24 pm
I have two questions-

First, I am interested in estimating a model where:
y1* = w1-w5+u1 where y* is a categorical variable while also estimating:
y2 = y1*+x1-x5+u2. There is some concern that the first equation may be over-specified. Is there a way to test this?

Second, assuming that y1* was continous, in which of the Tech files would I find the data to compute a Hausman test to see if I needed to instrument y1* at all?

Thank you.
 bmuthen posted on Tuesday, November 16, 2004 - 12:19 pm
Let me ask some question so I understand this setup - are the w1 and w5 exogenous variables and if so what do you mean by over-specified? Remind me, the Hausman test concerns left-out exogeneous variables that might make residuals correlate with the included exogenous variables, right? I am not sure the Mplus output has the information needed for this test (but it is a test we are interested in adding).
 Anonymous posted on Monday, April 18, 2005 - 5:48 pm
Can someone please help? How can the model be unidentified when I have 52 degrees of freedom? See below

Computation of degrees of freedom

Number of distinct sample moments = 91
Number of distinct parameters to be estimated = 39
Degrees of freedom = 91 - 39 = 52

The model is probably unidentified. In order to achieve
identifiability, it will probably be necessary to impose 3
additional constraints.

The (probably) unidentified parameters are marked.
 Linda K. Muthen posted on Tuesday, April 19, 2005 - 10:54 am
Can you send the full output to along with your license number. This is not enough information to answer your question. Note also that a model with positive degrees of freedom may not be identified due to a part of the model not being identified.
 Matt Moehr posted on Monday, December 04, 2006 - 7:42 am
The data I have come from a study where babies were given 3 different toys for sixty seconds each. The babies' behavior was timed and coded as Focused Attention (f), Casual Attention (c), or Not Looking (n). A sub-sample of the babies was coded by two raters and a reliability score, given as percent agreement, was calculated for each of the three categories:
Focused = 55.8%
Casual = 79.6%
Not Look = 95.8%

I found Linda's post from 1/23/2004, where she recommends using the formula (1-reliability)*sample variance to specify the error variance. My question is, can this same method be applied to latent variables with more than one measure? I tried the model below, but some of the results are confusing:

type = general missing h1;
estimator = ml;

mood1 BY f1@1 c1 n1*-1;
mood2 BY f2@1 c2 n2*-1;
mood3 BY f3@1 c3 n3*-1;

mood2 ON mood1;
mood3 ON mood2;


I triple checked my math, so I suspect something is going wrong because I have multiple measures on a single latent variable. Can I still use the inter-rater reliability to specify the error variance?
 Linda K. Muthen posted on Monday, December 04, 2006 - 9:23 am
You would only want to fixed the residual variance to correct for reliability when you have a single indicator. When you have a factor with several indicators, this captures the unreliability. You should remove the following statements:

 Matt Moehr posted on Monday, December 04, 2006 - 2:50 pm
My strategy on this analysis was to run three separate models with just one category of attention as the indicators This made 3 simple hidden Markov models, but I had to build in some type of assumption because they were all underidentified. I made the choice to bring in the inter-rater reliability because it seemed like the least restrictive assumption I could make. Then I began to wonder if I could make a model that used all three indicators for each trial, but I could never get this model to converge. When I went back and fixed the error variances, the model estimated just fine and most of the structural and measurement paths looked great. However, the standardized error variances were no longer equal to the inter-rater reliability, so I agree that this model is probably misspecified. Do you have any suggestions to improve model convergence in hidden Markov models? Is there an inherent problem in using multiple indicators, which are almost perfectly (negatively) correlated due to the mutually exclusive coding groups?
 Bengt O. Muthen posted on Thursday, December 07, 2006 - 6:27 pm
I am a little confused by your mentioning of both factor analysis and hidden markov, but let me focus on the latter. With a single observed binary indicator at each of 3 time points a hidden markov is identifiable if you estimate measurement error that is constrained to be invariant across time. If you have problems with this, send input, output, data and license number to

Yes, you don't want to use multiple indicators created from mutually exclusive coding groups. Such variables could be treated as nominal and then LTA (hidden markov) is possible.
 Matt Moehr posted on Friday, December 08, 2006 - 10:36 am
I'm also a little confused by the use of factor analysis and hidden Markov :-) , but I was handed this data long after the study was designed and executed. The theory we're working with says that 6-month old babies will show an habituation to novel stimulus, in this case new toys. However, interwoven with the habituation each baby should show early signs of innate temperament, or "personality" if you like. The main goal of the project is to measure temperament at 6-months and relate it to follow-up measures of temperament and psychosocial adjustment at age 24 months. Seems like a good idea, but my models don't like the variables for time-spans of attention. I think this is because they are mutually exclusive categories. For instance, if a baby spends a lot of time "Not Looking" during the trial, that baby is going to spend less time in "Focused Attention". There are only sixty seconds in each trial, so more time in one category means less time in another. Simple correlations among the residuals could account for this, but then the habituation that occurs between trials would be lost. I think what I'm trying to do is a basic LTA, but with a panel analysis (or hidden Markov?) stuck on the other side of the variables.

I'll try to clean up my syntax and send you all of the files.
 Bengt O. Muthen posted on Friday, December 08, 2006 - 6:26 pm
It sounds like you have a 3-category nominal variable (a single indicator) measured at two time points and that you want to do an LTA - see the UG for how to do that.
 Raji Srinivasan posted on Thursday, January 25, 2007 - 3:49 pm
Identification in Latent Class, Cluster Path Model

I have a data set with 49 clusters - and I am estimating a path model with 61 parameters- I get the following error message:


I am a novice here, and don't quite follow why the number of clusters has to exceed the number of parameters - can you please clarify?

Thanks in advance for your help!
 Linda K. Muthen posted on Thursday, January 25, 2007 - 5:14 pm
You can see formulas 167, 168, and 169 in Technical Appendix 8 which is on the website. Basically, an information matrix that is used in the computation of the standard errors is singular. It does not need to be inverted for the MLR estimator so we provide standard errors. This is a warning that we are not sure if they are accurate when there as less clusters than parameters. The affect of this matrix being singular has not been studied.
 Raji Srinivasan posted on Thursday, January 25, 2007 - 7:30 pm
Thanks for the prompt response!
Much appreciated...

 dm posted on Sunday, May 20, 2007 - 12:54 pm
Hi, I am using the following model in a paper:

MODEL: Y1 ON Y2 Y3 X1 X2 X3;
Y2 ON Y3 X1 X4 X5 X6 X7;
Y3 ON Y1 X1 X4 X5 X2 X3 X8 X9;

Y1, Y2 and Y3 are endogenous variables and X1 … X9 are exogenous variables.

The paper received a R&R from a major journal and one of the reviewers questioned whether MPLUS can solve the causation (feedback effect) between Y1 and Y3.

(1) The reviewer said, “I do not see how your model can be identified without some instruments for the variables “Y3” and “Y1.”

Do I really need instrumental variables? I think if the model cannot be identified, MPLUS will generate an error message (it didn’t in my case). If I don’t need instrumental variables, how should I respond to the reviewer?

(2) The reviewer said, “Your very schematic description of the model (you need to provide its graphic representation) does not give me any idea how your model is identified.”

For “graphical representation,” do you think the reviewer just wants a graph indicating possible causal paths between all the variables?

(3) It seems that the reviewer wants more technical discussion, so could you please give me suggestions on methodological details of model identification in MPLUS (for the procedure I used)?
 Bengt O. Muthen posted on Sunday, May 20, 2007 - 1:26 pm
(1)The reciprocal interaction between y1 and y3 is identified because your model fulfills the rule of having at least one x variable that influences y1 and not y3 and at least one x variable that influences y3 and not y1. I think Bollen's SEM book covers this. Empirically, you are right that Mplus would complain if the model was not identified.

(2) Draw the model and also refer to a section in some SEM book for identification.

(3) Identification matters in Mplus is the same as in other SEM, so Bollen's book is a good resource.
 Richard E. Zinbarg posted on Tuesday, May 22, 2007 - 9:37 am
Dear Linda and/or Bengt,
I know that if a portion of a model is under-identified then the entire model is under-identified (e.g., a second-order CFA with two first-order factors and one second-order factor is always under-identified in the absence of a constraint on the higher-order loadings because the second-order portion of the model is underidentified regardless of whether the first-order portion is identified or over-identified). What I am wondering is whether an overall model is still overidentified if a portion of it is just identified? As one example, consider a second-order CFA with three first-order factors and one second-order factor and four observed indicators of each first-order factor. The first-order portion of the model is over-identified but the second-order portion is just identified. Is the overall model over-identified?
Rick Zinbarg
 Linda K. Muthen posted on Tuesday, May 22, 2007 - 9:50 am
The overall model is over-identified as far as degrees of freedom. The just-identified part of the model fits perfectly so the test of fit applies to the part of the model that is over-identified.
 Richard E. Zinbarg posted on Wednesday, May 23, 2007 - 9:39 pm
thanks very much!
 Josue Almansa Ortiz posted on Monday, April 28, 2008 - 12:22 pm
I've adjusted 2 different models but I think I've obtained the same results żare they equivalent? - because I've expected to found some difference.
(All observed variables are continuous and normally distributed).

model_1 -> f1 BY y1 y2 y3 x;

model_2 -> f1 BY y1 y2 y3; x ON f1;

I thought that if the error distribution of the "structural part" (x ON f1) is different to the error-distribution of the "measurement part" then both models could be different, but if the error distribution is the same then it makes no difference, and both models are equivalent. Is it correct?
 Linda K. Muthen posted on Monday, April 28, 2008 - 2:27 pm
f1 BY x is the same as x ON f1 so these models are the same.
 Maša Vidmar posted on Monday, June 01, 2009 - 6:32 pm
I am running a CFA with several constructs, one of which has only 1 indicator. I fixed error variance to (1 – reliability) * sample variance. Would you happen to know the reference for that formula? I tried looking in some multivariate and SEM textbooks, but I could not find it. Thx!
 Linda K. Muthen posted on Tuesday, June 02, 2009 - 9:35 am
I don't now offhand. I would think the Bollen book might discuss this.
 Maša Vidmar posted on Tuesday, June 02, 2009 - 5:31 pm
I cannot get the Bollen book (Structural equations with latent variables) is not on Psyinfo nor in any library in our country. I also looked at his paper ''Latent variables in psychology and the social sciences'', no success. Any other suggestions? Thx.
 Linda K. Muthen posted on Thursday, June 04, 2009 - 9:20 am
This should be documented in most SEM books. We show this in slide 43 of our Topic 1 course handout. You can try Google or ask on SEMNET. Does anyone else on this forum know of a reference?
 Fernando Terrés de Ercilla posted on Sunday, June 07, 2009 - 3:51 am
Maša, as Linda says, Bollen's book, chapter 5 ("The consequences of measurement error") is the standard reference.
Other, easy-to-find ebook, references are:
Schumaker&Lomax: A Beginner's Guide to Structural Equation Modeling (2nd. ed), pags. 198-199
Kline: Principles and Practice of Structural Equation Modeling (2nd. ed), pags. 229-231
(Or try Google with: latent variable with single indicator).
 Vlad posted on Wednesday, October 21, 2009 - 8:48 am
I am estimating the model with 3-classes and always get this messege from mplus: WARNING: WHEN ESTIMATING A MODEL WITH MORE THAN TWO CLASSES, IT MAY BE NECESSARY TO INCREASE THE NUMBER OR RANDOM STARTS USING THE STARTS OPTION TO AVOID LOCAL MAXIMA. I've tried to use starts but nothing has changed. Any suggestion?
 Amir Sariaslan posted on Wednesday, October 21, 2009 - 8:53 am
The message is just a reminder. It will pop up no matter how many starting values you'll specify.
 Zairul Nor Deana posted on Friday, April 23, 2010 - 11:20 am
I've question for underidentified model with 2 indicators. I did equate both loadings for this model. However the results give me one loading=1.00, se=0.000 so that est/se=999.00 and p=999. The other loading is 1.42 with se=.056, est/se=25.35.
My question, what is that means with est/se=999 and p=999?

 Linda K. Muthen posted on Friday, April 23, 2010 - 12:17 pm
The 999 means the value can not be computed. A fixed parameter has no standard error or significance test. It does not sound like you held the loadings equal. To do this,

f BY y1* (1)
y2 (1);
 Hillary Schafer posted on Friday, December 10, 2010 - 9:35 am

After reading through some of the earlier postings, it looks as though a globally identified model will estimate even if there are some locally non-identified parameters. Is that correct, or is there a warning if local under-identification is present?

If there is no warning, does this mean that it is safe to interpret all model parameters or the locally identified parameters?

Thanks for your help!
 Linda K. Muthen posted on Sunday, December 12, 2010 - 10:40 am
We check for local not global identification. I think in 99% of the cases, Mplus will catch non-identification and give a message.

If you want to be certain about identification, you can use the STARTS option to generate random starts.

Perhaps you mean that some parameters are not identified and others are.
 Hillary Schafer posted on Monday, December 13, 2010 - 6:53 am

Thank you for your response. Yes, I was asking about how Mplus would handle a situation in which some parameters are not identified and others are. From your response, it sounds like Mplus will notice this and give a warning message in almost all circumstances. Is that correct?
 Linda K. Muthen posted on Monday, December 13, 2010 - 7:00 am
 Kip Sorgen posted on Tuesday, February 08, 2011 - 10:37 am
I have a latent construct with three indicators that is just identified in CFA and explains 92% of the variance. What are some considerations of having a factor with zero degrees of freedom when including it in the full SEM model?
 Linda K. Muthen posted on Tuesday, February 08, 2011 - 11:03 am
The major one for me is that you can't test its fit.
 Andres Fandino-Losada posted on Thursday, February 16, 2012 - 1:24 am
In a measurement model; what is the relation between the reliability of a single indicator and its sensibility and specificity?
 Linda K. Muthen posted on Friday, February 17, 2012 - 2:02 pm
I don't know if there is a relationship between reliability and sensitivity and specificity. You might look at the LCA literature.
 Joni posted on Thursday, March 22, 2012 - 12:41 pm
I am a very new user to Mplus. And need a question answered about identification. I have a latent factor with 3 indicators that will be part of larger SEM. I wanted to check my measurement models before I added them to the larger model. This is my code:

CATEGORICAL b15a b15b b15c;
Weight W1;
cluster C1;
Type = complex;
NEG BY b15a* b15b b15c@1 ;

My model has 0 degrees of freedom for the Chi-Square Test of Model Fit and therefore don't get estimates for the Test of fit or RMSEA and my TLI/CFI=1, does this mean I need to fix my factor variance? And if so, how do I do that? Thanks!
 Linda K. Muthen posted on Thursday, March 22, 2012 - 12:50 pm
A factor with three indicators is just-identified. Model fit cannot be assessed for a factor with less than four indicators.
 Cecily Na posted on Wednesday, October 31, 2012 - 12:26 pm
I have a model with two latent factors and other observed covariates. Each latent factor has two indicators. One latent factor together with other covariates cause the other latent factor. No errors are correlated. Is this model identified? How do these two factors borrow information from each other?
Thanks a lot!
 Bengt O. Muthen posted on Wednesday, October 31, 2012 - 5:14 pm
Sounds like an identified model given that a model with 2 factors that are correlated and each has 2 indicators is identified. The covariances between the 2 sets of factor indicators make it identified. And your model also has covariates.
 Paula Vagos posted on Friday, December 14, 2012 - 4:12 am
I am trying to test a second-order model, with two first-order factors, each with 8 indicators. I fexed the paths between the two first order factors and the higher-order factor. Would this model be possible/ identified?

Thank you.
 Linda K. Muthen posted on Friday, December 14, 2012 - 12:31 pm
If both factor loadings are fixed, then the model would be identified. But I wonder what the point of this is. If they are fixed at one, the one parameter that is estimated is the factor variance which is the covariance between the two factor indicators.
 Sakshi Bhargava posted on Thursday, September 17, 2015 - 12:36 pm
Hi Dr. Muthen,
I ran SEM in Mplus. I am getting the following fit indices for my model:

Chi-Sq (5) = 3.89, ns; RMSEA = .00; CFI = 1.00 and TLI = 1.08; SRMR = .017

With these fit indices, is the model fit considered good or is it a just identified model?

Thank you
 Bengt O. Muthen posted on Thursday, September 17, 2015 - 6:00 pm
For a just-identified model you would get zero chi-square. Take a look at our short course video and handout for Topic 1.
 Sakshi Bhargava posted on Friday, September 18, 2015 - 9:01 am
Okay. Thank you so much.
 Gabrielle Daniels-Gombert posted on Saturday, January 16, 2016 - 4:43 am
Hello everyone. I'm new to CFA & SEM and
have 2 questions on identification which I hope you can help with.
Three constructs in my model are measured by 3 items (existing scales, not my own). Naturally, this produces just-identified models. But when I place these constructs together with others (e.g. in a 2-factor or larger model) I get excellent Fit statistics, CR, AVE, etc.
Q1. Is it acceptable then to continue using these three constructs within the larger measurement model?
Q2. If so, presumably I declare in my write up that as single-factor models they produced saturated models.
Thank you in advance for your advice
 Bengt O. Muthen posted on Saturday, January 16, 2016 - 6:30 am
Q1. Yes. You just have to remember that any misfit is due to correlations among items for different constructs.

Q2. Right. Pointing out that this is a weakness because you cannot reject the model for each construct separately.
 Gabrielle Daniels-Gombert posted on Saturday, January 16, 2016 - 9:28 am
Thank you very much for your fast response and advice Dr Muthén. That has really helped.
 Yanick Brice posted on Saturday, January 16, 2016 - 6:49 pm
I am new to Mplus. I am running a 1-1-1 mediation model and Mplus issued this warning: Sample covariance matrix is singular. The standard error of parameter estimates may not be trustworthy... 1.) How does one typically resolve such issue in Mplus? 2) Should the entire set of results be dismissed? 3) How is such issue typically handled in a research report? Please advise. Thank you.
 Linda K. Muthen posted on Sunday, January 17, 2016 - 4:49 pm
Please send the output and your license number to
 Jason Thomas posted on Monday, February 29, 2016 - 10:50 am

I am trying to confirm the identification of an SEM using the 2-step rule. For the first step (treat the measurement model like a CFA), I am confused if certain observed endogenous variables need to be treated as single indicators for latent variables. In Mplus the model is

F1 BY y1 y2 y3 y4;
F2 BY y5 y6 y7 y8;

F1 ON x1 x2 x3 x4;
F2 ON x1 x2 x3 x4;
y9 ON F1 F2 x1 x2 x3 x4;
y10 ON F1 F2 y9 x4;
y11 ON F1 F2 y9 x4;
y12 ON F1 F2 y9 x4;
y13 ON F1 F2 y9 x4;
y14 ON y13 y12 y11 y10 F1 F2 y9 y4;


I am trying to apply the rank condition, which requires no restrictions on Phi (covariance matrix of disturbance terms for latent variables). Do y9 - y14 need to be treated as single indicators of latent variables (and thus Phi is really an 8x8 matrix, as opposed to a 2x2 matrix for F1 and F2)? Any advice you can give is greatly appreciated!
 Linda K. Muthen posted on Monday, February 29, 2016 - 4:51 pm
You should ask this on a general discussion forum like SEMNET.
 Jason Thomas posted on Monday, February 29, 2016 - 5:22 pm
will do, thanks!
 Maartje van Sonsbeek posted on Monday, May 02, 2016 - 8:38 am
Hi everyone.

I have an additional question about CFA with constructs that have only three items. I have a questionnaire with five subscales. Because the subscales differ in length (e.g. 20 items vs 5 items), I have conducted separate CFA's for each subscale. However, two subscales only have three items and thus produce just-identified models.

Based on the post of Gabrielle Daniels-Gombert, I was wondering:

1) Is it acceptable to conduct a combined CFA for these two subscales and report the accompanying fit indices? Or how can I otherwise deal with this problem?
2) If it is acceptable to conduct a combined CFA, how do I report this in my paper? Could it be something like: "Because both X and Y subscales have only three items, the models of these subscale were just-identified and no meaningful fit indices could be computed. Therefore, we conducted a two-construct CFA with these subscales. The fit of this model was..."
Thank you in advance!
 Bengt O. Muthen posted on Monday, May 02, 2016 - 9:44 am
1) - 2). Yes.

You do test the 1-factor structure for the 3-item part by including it in a bigger model because this implies a strong structure for the covariances between those 3 items and the items on other factors.
 Maartje van Sonsbeek posted on Tuesday, May 03, 2016 - 11:31 pm
Dear Bengt,

Thank you for your quick en helpful response!

Best, Maartje
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