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 Louis De Page posted on Tuesday, August 02, 2011 - 5:46 am
Dear Professor,

I'm currently trying to grasp the principle of multi-group ESEM (as outline in example 5.27 of the user manual). I do understand the rationale behind this lines of code for fixing factor covariance

f1 WITH f2 (1);

but how should I enter a four-factor structure? Like this?

f1 WITH f2 (1);
f1 WITH f3 (1);
f1 WITH f4 (1);
f2 WITH f3 (1);
f2 WITH f4 (1);
f3 WITH f4 (1);

Is this right? Is there a more sober way to do so?


 Linda K. Muthen posted on Tuesday, August 02, 2011 - 1:56 pm
f1 WITH f2 (1);

The code above does not fix the factor covariance. It holds it equal across groups.

If you have several factors and want to hold each covariance equal across groups, you would specify:

f1 WITH f2 (1);
f1 WITH f3 (2);
f1 WITH f4 (3);
f2 WITH f3 (4);
f2 WITH f4 (5);
f3 WITH f4 (6);

The way you specified it, all factor covariances are held equal across groups and to each other.
 Louis De Page posted on Wednesday, August 03, 2011 - 7:05 am
Thank you very much for this quick reply!

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