

Generating a new latent variable that... 

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Shige Song posted on Wednesday, December 20, 2006  9:19 pm



the difference of another two latent variables. For example, I have two sequential growth processes and I want to get the difference of the two intercepts:  level trend  ht0*12 ht1*11 ht2*10 ht3*9 ht4*8 ht5*7 ht6*6 ht7*5 ht8*4 ht9*3 ht10*2 ht11@1 ht12@0; i s  ht91@0 ht94@1 ht98*2; dif  i  level;  where "level" and "trend" are latent growth factors for the first process and "i" and "s" are latent growth factors for the second process. I want to create a new latent variable that is the difference of the two latent growth factors "level" and "i". Mplus reports that this is a syntax error "Unable to expand variable list: I  LEVEL" The interaction of two latent variables can be generated using the "xwith" statement, but I could not find how to get the difference between two latent variable . Thanks for any suggestions! Shige 


You have to define a new factor that is equal to i  level. You can do that as follows: fdif by; fdif on i@1 level@1; fdif@0; [fdif@0]; This defines the new factor fdif as fdif = 0 + 1*i1*level+0 

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